What is the solution for (v-1)/(v^2-2v+1)dv=-1/y dy ?

The solution for (v-1)/(v^2-2v+1)dv=-1/y dy is y=(c_{1})/(v-1)

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(v-1)/(v^2-2v+1)dv=-1/y dy

\frac{v - 1}{v ^{2} - 2 v + 1} d v = - \frac{1}{y} d y

y = \frac{c _{1}}{v - 1}

Solution steps

\frac{v - 1}{v ^{2} - 2 v + 1} d v = - \frac{1}{y} d y

Solve separable ODE:

y = \frac{c _{1}}{v - 1}

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What is the solution for (v-1)/(v^2-2v+1)dv=-1/y dy ?
The solution for (v-1)/(v^2-2v+1)dv=-1/y dy is y=(c_{1})/(v-1)