What is the derivative of (2x^3+7)^2 ?

The derivative of (2x^3+7)^2 is 12x^2(2x^3+7)

What is the first derivative of (2x^3+7)^2 ?

The first derivative of (2x^3+7)^2 is 12x^2(2x^3+7)

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derivative of

(2 x^{3} + 7)^{2}

12 x^{2} (2 x^{3} + 7)

Solution steps

\frac{d}{d x} ((2 x^{3} + 7)^{2})

Apply the chain rule:

2 (2 x^{3} + 7) \frac{d}{d x} (2 x^{3} + 7)

= 2 (2 x^{3} + 7) \frac{d}{d x} (2 x^{3} + 7)

\frac{d}{d x} (2 x^{3} + 7) = 6 x^{2}

= 2 (2 x^{3} + 7) \cdot 6 x^{2}

Simplify

= 12 x^{2} (2 x^{3} + 7)

\int x^{2} \cdot 4^{- x} d x

f (x) = x^{2}, (0, - 25)

\int 2 x^{2} + 2 d x

\int csc^{7} (x) d x

\int (\frac{3}{2})^{2} d x

What is the derivative of (2x^3+7)^2 ?
The derivative of (2x^3+7)^2 is 12x^2(2x^3+7)
What is the first derivative of (2x^3+7)^2 ?
The first derivative of (2x^3+7)^2 is 12x^2(2x^3+7)