What is area x=y^2-7,x=1-y^2,-2<= y<= 2 ?

The answer to area x=y^2-7,x=1-y^2,-2<= y<= 2 is 64/3

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area x=y^2-7,x=1-y^2,-2<= y<= 2

area

x = y^{2} - 7, x = 1 - y^{2}, - 2 \leq y \leq 2

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} y^{2} - 7 - (1 - y^{2}) d y

Solve

\int_{- 2}^{2} y^{2} - 7 - (1 - y^{2}) d y : \frac{64}{3}

The area is:

= \frac{64}{3}

\frac{d y}{d t} t + y = 2 t

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\frac{\partial}{\partial y} (7 x^{7} y^{4} + 2 x^{8} y^{6})

\int_{0}^{9} 6 - 2 x d x

\int \frac{x}{25 + 16 x ^{4}} d x

What is area x=y^2-7,x=1-y^2,-2<= y<= 2 ?
The answer to area x=y^2-7,x=1-y^2,-2<= y<= 2 is 64/3