What is (\partial)/(\partial y)(7x^7y^4+2x^8y^6) ?

The answer to (\partial)/(\partial y)(7x^7y^4+2x^8y^6) is 28x^7y^3+12x^8y^5

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(\partial)/(\partial y)(7x^7y^4+2x^8y^6)

\frac{\partial}{\partial y} (7 x^{7} y^{4} + 2 x^{8} y^{6})

28 x^{7} y^{3} + 12 x^{8} y^{5}

Solution steps

\frac{\partial}{\partial y} (7 x^{7} y^{4} + 2 x^{8} y^{6})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (7 x^{7} y^{4}) + \frac{\partial}{\partial y} (2 x^{8} y^{6})

\frac{\partial}{\partial y} (7 x^{7} y^{4}) = 28 x^{7} y^{3}

\frac{\partial}{\partial y} (2 x^{8} y^{6}) = 12 x^{8} y^{5}

= 28 x^{7} y^{3} + 12 x^{8} y^{5}

\int_{0}^{9} 6 - 2 x d x

\int \frac{x}{25 + 16 x ^{4}} d x

\int \frac{x ^{2}}{6 - x} d x

x \to 2 lim (f (x))

y = x^{3} - 9 x^{2} + 18 x, y = - x^{3} + 9 x^{2} - 18 x

What is (\partial)/(\partial y)(7x^7y^4+2x^8y^6) ?
The answer to (\partial)/(\partial y)(7x^7y^4+2x^8y^6) is 28x^7y^3+12x^8y^5