What is area y=x^3-9x^2+18x,y=-x^3+9x^2-18x ?

The answer to area y=x^3-9x^2+18x,y=-x^3+9x^2-18x is 81

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area y=x^3-9x^2+18x,y=-x^3+9x^2-18x

area

y = x^{3} - 9 x^{2} + 18 x, y = - x^{3} + 9 x^{2} - 18 x

81

Solution steps

Apply the area formula:

\int_{0}^{6} x^{3} - 9 x^{2} + 18 x - (- x^{3} + 9 x^{2} - 18 x) d x

Solve

\int_{0}^{6} x^{3} - 9 x^{2} + 18 x - (- x^{3} + 9 x^{2} - 18 x) d x : 81

The area is:

= 81

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What is area y=x^3-9x^2+18x,y=-x^3+9x^2-18x ?
The answer to area y=x^3-9x^2+18x,y=-x^3+9x^2-18x is 81