What is the integral from 1 to 3 of x^2 ?

The integral from 1 to 3 of x^2 is 26/3

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integral from 1 to 3 of x^2

\int_{1}^{3} x^{2} d x

\frac{26}{3}

Decimal

8.66666 \dots

Solution steps

\int_{1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{3}

= [\frac{x ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= \frac{26}{3}

x \to 4 + lim (\frac{- 3}{8 - 2 x})

\frac{d}{d x} (6 x^{1.5} - 4 x^{0.5})

\frac{\partial}{\partial x} (x e^{- y} + y e^{- x})

e^{t} sin (6 t)

\frac{d}{d x} (sin (x) x)

What is the integral from 1 to 3 of x^2 ?
The integral from 1 to 3 of x^2 is 26/3