What is the derivative of 2x^7-x^5+5x^3-8x+4 ?

The derivative of 2x^7-x^5+5x^3-8x+4 is 14x^6-5x^4+15x^2-8

What is the first derivative of 2x^7-x^5+5x^3-8x+4 ?

The first derivative of 2x^7-x^5+5x^3-8x+4 is 14x^6-5x^4+15x^2-8

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\frac{d}{d x} (2 x^{7} - x^{5} + 5 x^{3} - 8 x + 4)

14 x^{6} - 5 x^{4} + 15 x^{2} - 8

Solution steps

\frac{d}{d x} (2 x^{7} - x^{5} + 5 x^{3} - 8 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{7}) - \frac{d}{d x} (x^{5}) + \frac{d}{d x} (5 x^{3}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{7}) = 14 x^{6}

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (4) = 0

= 14 x^{6} - 5 x^{4} + 15 x^{2} - 8 + 0

Simplify

= 14 x^{6} - 5 x^{4} + 15 x^{2} - 8

\frac{d}{d x} (\frac{( 5 x + 3 )}{3 e ^{x}})

\int sin (x) sec^{5} (x) d x

f (x) = x^{2} - 9, at x = 2

\frac{8}{x ^{3}}

\frac{d}{d x} ((5 x^{3})^{x})

What is the derivative of 2x^7-x^5+5x^3-8x+4 ?
The derivative of 2x^7-x^5+5x^3-8x+4 is 14x^6-5x^4+15x^2-8
What is the first derivative of 2x^7-x^5+5x^3-8x+4 ?
The first derivative of 2x^7-x^5+5x^3-8x+4 is 14x^6-5x^4+15x^2-8