What is the derivative of 8^x ?

The derivative of 8^x is 3ln(2)*8^x

What is the first derivative of 8^x ?

The first derivative of 8^x is 3ln(2)*8^x

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derivative of

8^{x}

3 ln (2) \cdot 8^{x}

Solution steps

\frac{d}{d x} (8^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 8^{x} ln (8)

Simplify

ln (8) : 3 ln (2)

= 3 ln (2) \cdot 8^{x}

\frac{d}{d x} (\frac{cot ( x )}{1 - sin ( x )})

\frac{d}{d x} (sin (8 x) e^{4 x})

ln (x^{2} - 4)

\int sin (x) (- 8 x cos (2 x)) d x

x \to 0 lim (3 x + 2)