What is the integral from 2 to 5 of 2x^3 ?

The integral from 2 to 5 of 2x^3 is 609/2

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integral from 2 to 5 of 2x^3

\int_{2}^{5} 2 x^{3} d x

\frac{609}{2}

Decimal Notation

304.5

Solution steps

\int_{2}^{5} 2 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{2}^{5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{2}^{5}

= 2 [\frac{x ^{4}}{4}]_{2}^{5}

Compute the boundaries:

\frac{609}{4}

= 2 \cdot \frac{609}{4}

Simplify

= \frac{609}{2}

\frac{d y}{d x} = - y^{3}

y = x^{2} - 8 x + 9, (1, 2)

\frac{d}{d x} (u e^{- x})

\int 361 - x^{2} d x

\int - 2 x^{- 1} d x

What is the integral from 2 to 5 of 2x^3 ?
The integral from 2 to 5 of 2x^3 is 609/2