What is area y=x^3+x^2-6x,y=6x ?

The answer to area y=x^3+x^2-6x,y=6x is 937/12

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area y=x^3+x^2-6x,y=6x

area

y = x^{3} + x^{2} - 6 x, y = 6 x

\frac{937}{12}

Decimal Notation

78.08333 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{3} + x^{2} - 12 x d x

Solve

\int_{- 4}^{3} x^{3} + x^{2} - 12 x d x : \frac{937}{12}

The area is:

= \frac{937}{12}

e^{(3 t)} (4 cos (3 t) - \frac{10}{3} sin (3 t))

x \to - 1 + lim (\frac{x}{∣ x + 1 ∣})

y, y = x e^{y}

\int_{- 3}^{- 2} (2 x (3 - x^{2})^{3}) d x

f (x) = cos (x), at x = π