What is the integral of 7x^2+3x-3 ?

The integral of 7x^2+3x-3 is (7x^3)/3+(3x^2)/2-3x+C

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integral of 7x^2+3x-3

\int 7 x^{2} + 3 x - 3 d x

\frac{7 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 3 x + C

Solution steps

\int 7 x^{2} + 3 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 x^{2} d x + \int 3 x d x - \int 3 d x

\int 7 x^{2} d x = \frac{7 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 3 d x = 3 x

= \frac{7 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 3 x

Add a constant to the solution

= \frac{7 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 3 x + C

\frac{\partial}{\partial x} (2 y e^{2 x y})

f (x) = \frac{x}{1 - ln ( x - 6 )}

2 x + 2 y \frac{d y}{d x} = 0

\int_{0}^{5 r} 2 (25 r^{2} - y^{2}) d y

\int \frac{1}{y ^{3} + 1} d y

What is the integral of 7x^2+3x-3 ?
The integral of 7x^2+3x-3 is (7x^3)/3+(3x^2)/2-3x+C