What is the solution for 2x+2y(dy)/(dx)=0 ?

The solution for 2x+2y(dy)/(dx)=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

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2x+2y(dy)/(dx)=0

2 x + 2 y \frac{d y}{d x} = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

2 x + 2 y \frac{d y}{d x} = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\int_{0}^{5 r} 2 (25 r^{2} - y^{2}) d y

\int \frac{1}{y ^{3} + 1} d y

y = 6 tan (x), at x = \frac{π}{3}

\int \frac{10 x ^{2} - 9 x + 20}{x ^{3} + 4 x} d x

x y^{^{'}} + x y - y^{^{'}} - 2 y = 0

What is the solution for 2x+2y(dy)/(dx)=0 ?
The solution for 2x+2y(dy)/(dx)=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}