What is (\partial)/(\partial x)(x^2ln(y+1)) ?

The answer to (\partial)/(\partial x)(x^2ln(y+1)) is 2xln(y+1)

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(\partial)/(\partial x)(x^2ln(y+1))

\frac{\partial}{\partial x} (x^{2} ln (y + 1))

2 x ln (y + 1)

Solution steps

\frac{\partial}{\partial x} (x^{2} ln (y + 1))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (y + 1) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= ln (y + 1) \cdot 2 x^{2 - 1}

Simplify

= 2 x ln (y + 1)

3 x, x

\int \frac{sec ^{2} ( 3 x )}{1 + tan ( 3 x )} d x

y = x^{2} - 3 x - 5, (2, - 7)

f (x) = 3 x^{2} - 12 x + 1, (0, 1)

\frac{d}{d x} (\frac{x ^{3}}{3} - 2 x^{2} - 5 x)

What is (\partial)/(\partial x)(x^2ln(y+1)) ?
The answer to (\partial)/(\partial x)(x^2ln(y+1)) is 2xln(y+1)