What is (\partial)/(\partial x)(y^2-xy) ?

The answer to (\partial)/(\partial x)(y^2-xy) is -y

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(\partial)/(\partial x)(y^2-xy)

\frac{\partial}{\partial x} (y^{2} - x y)

- y

Solution steps

\frac{\partial}{\partial x} (y^{2} - x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x y) = y

= 0 - y

Simplify

= - y

\frac{d y}{d x}, y = ln (x)

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 2)^{7})

x \to - 1 - lim (\frac{3}{x + 1})

f^{^{'}} (x) = \frac{5}{6 x ^{5}}

\int \frac{sin ( x ) + cos ( x )}{tan ( x )} d x

What is (\partial)/(\partial x)(y^2-xy) ?
The answer to (\partial)/(\partial x)(y^2-xy) is -y