What is the derivative of f(x)=3x^2-1 ?

The derivative of f(x)=3x^2-1 is 6x

What is the first derivative of f(x)=3x^2-1 ?

The first derivative of f(x)=3x^2-1 is 6x

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derivative of

f (x) = 3 x^{2} - 1

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (1) = 0

= 6 x - 0

Simplify

= 6 x

\frac{d y}{d x} = x + 6 y, y (0) = 2

f (x) = \frac{4 x + 5}{x - 1}, (2, 13)

2 x, 2 x

n = 1 \sum \infty (\frac{1}{2})^{2 n - 1}

\frac{\partial}{\partial x} (x z)

What is the derivative of f(x)=3x^2-1 ?
The derivative of f(x)=3x^2-1 is 6x
What is the first derivative of f(x)=3x^2-1 ?
The first derivative of f(x)=3x^2-1 is 6x