What is the tangent of f(x)=(4x+5)/(x-1),(2,13) ?

The tangent of f(x)=(4x+5)/(x-1),(2,13) is y=-9x+31

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tangent of f(x)=(4x+5)/(x-1),(2,13)

tangent of

f (x) = \frac{4 x + 5}{x - 1}, (2, 13)

y = - 9 x + 31

Solution steps

Find the slope of

f (x) = \frac{4 x + 5}{x - 1} : \frac{df ( x )}{d x} = - \frac{9}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x + 5}{x - 1}

(2, 13) : m = - 9

Find the line with slope m=

- 9

and passing through

(2, 13) : y = - 9 x + 31

y = - 9 x + 31

2 x, 2 x

n = 1 \sum \infty (\frac{1}{2})^{2 n - 1}

\frac{\partial}{\partial x} (x z)

2 x^{3} + 3 x^{2} - 12 x + 3

f (x) = (x^{2} - 4)^{2}

What is the tangent of f(x)=(4x+5)/(x-1),(2,13) ?
The tangent of f(x)=(4x+5)/(x-1),(2,13) is y=-9x+31