What is the derivative of f(x)=(x^2-4)^2 ?

The derivative of f(x)=(x^2-4)^2 is 4x(x^2-4)

What is the first derivative of f(x)=(x^2-4)^2 ?

The first derivative of f(x)=(x^2-4)^2 is 4x(x^2-4)

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derivative of

f (x) = (x^{2} - 4)^{2}

4 x (x^{2} - 4)

Solution steps

\frac{d}{d x} ((x^{2} - 4)^{2})

Apply the chain rule:

2 (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

= 2 (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= 2 (x^{2} - 4) \cdot 2 x

Simplify

= 4 x (x^{2} - 4)

3 x e^{- k x}

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{( 1 + x )})

x \to 6 lim (\frac{x - 6}{x - 6})

\int 4 x - x^{2} d x

P (x) = x (x - 8) (x + 5)

What is the derivative of f(x)=(x^2-4)^2 ?
The derivative of f(x)=(x^2-4)^2 is 4x(x^2-4)
What is the first derivative of f(x)=(x^2-4)^2 ?
The first derivative of f(x)=(x^2-4)^2 is 4x(x^2-4)