What is the integral from 0 to 2pi of cos(θ) ?

The integral from 0 to 2pi of cos(θ) is 0

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integral from 0 to 2pi of cos(θ)

\int_{0}^{2 π} cos (θ) d θ

0

Solution steps

\int_{0}^{2 π} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= [sin (θ)]_{0}^{2 π}

Compute the boundaries:

0

= 0

\frac{\partial}{\partial t} (\frac{s - 2 r}{t})

\frac{y ^{3}}{27} + \frac{9}{4 y}

\int \frac{1}{( x + x ^{2} )} d x

\int sin (4 x + 3) d x

\frac{d y}{d x} + y = x + 1

What is the integral from 0 to 2pi of cos(θ) ?
The integral from 0 to 2pi of cos(θ) is 0