What is the derivative of y=x^2+4x^3 ?

The derivative of y=x^2+4x^3 is 2x+12x^2

What is the first derivative of y=x^2+4x^3 ?

The first derivative of y=x^2+4x^3 is 2x+12x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{2} + 4 x^{3}

2 x + 12 x^{2}

Solution steps

\frac{d}{d x} (x^{2} + 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x^{3})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

= 2 x + 12 x^{2}

\frac{1}{y ( 1 - 0.0005 y )} d y = d x, y (0) = 1

\frac{d}{d x} (\frac{5}{cos ( x )})

\int 10 x ln (2 x) d x

\int \frac{4}{x + 3} d x

f (x) = lo g_{3} (3 x - 6)

What is the derivative of y=x^2+4x^3 ?
The derivative of y=x^2+4x^3 is 2x+12x^2
What is the first derivative of y=x^2+4x^3 ?
The first derivative of y=x^2+4x^3 is 2x+12x^2