What is the integral of 10xln(2x) ?

The integral of 10xln(2x) is 10(1/2 x^2ln(2x)-(x^2)/4)+C

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integral of 10xln(2x)

\int 10 x ln (2 x) d x

10 (\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4}) + C

Solution steps

\int 10 x ln (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int x ln (2 x) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} ln (2 x) - \int \frac{x}{2} d x

= 10 (\frac{1}{2} x^{2} ln (2 x) - \int \frac{x}{2} d x)

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 10 (\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4})

Add a constant to the solution

= 10 (\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4}) + C

\int \frac{4}{x + 3} d x

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\int_{0}^{2} 5 t^{9} d t

\frac{d}{d x} (x^{6} e^{5 x})

x \to 0 lim (\frac{( x ^{2} )}{x - 1})

What is the integral of 10xln(2x) ?
The integral of 10xln(2x) is 10(1/2 x^2ln(2x)-(x^2)/4)+C