What is the integral from 0 to 2 of 5t^9 ?

The integral from 0 to 2 of 5t^9 is 512

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integral from 0 to 2 of 5t^9

\int_{0}^{2} 5 t^{9} d t

512

Solution steps

\int_{0}^{2} 5 t^{9} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{2} t^{9} d t

Apply the Power Rule

: [\frac{t ^{10}}{10}]_{0}^{2}

= 5 [\frac{t ^{10}}{10}]_{0}^{2}

Compute the boundaries:

\frac{512}{5}

= 5 \cdot \frac{512}{5}

Simplify

= 512

\frac{d}{d x} (x^{6} e^{5 x})

x \to 0 lim (\frac{( x ^{2} )}{x - 1})

y = \frac{1}{x ^{3}}, (2, \frac{1}{8})

\frac{d}{d x} (5 + 4 x)

\frac{\partial}{\partial y} (cos (2 x) sin (3 y))

What is the integral from 0 to 2 of 5t^9 ?
The integral from 0 to 2 of 5t^9 is 512