What is (\partial)/(\partial y)(2x-3y+5) ?

The answer to (\partial)/(\partial y)(2x-3y+5) is -3

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(\partial)/(\partial y)(2x-3y+5)

\frac{\partial}{\partial y} (2 x - 3 y + 5)

- 3

Solution steps

\frac{\partial}{\partial y} (2 x - 3 y + 5)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (3 y) + \frac{\partial}{\partial y} (5)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (3 y) = 3

\frac{\partial}{\partial y} (5) = 0

= 0 - 3 + 0

Simplify

= - 3

(x^{2} + 2) (x^{3} + 6)

\int cos (x) e^{- s x} d x

\frac{\partial}{\partial x} (x^{2} + 1 + z^{3})

(\frac{5}{8}, - 2), (- \frac{1}{4}, - \frac{1}{4})

y^{2} - x y - 10 = 0, (- 3, - 5)

What is (\partial)/(\partial y)(2x-3y+5) ?
The answer to (\partial)/(\partial y)(2x-3y+5) is -3