What is the tangent of y^2-xy-10=0,(-3,-5) ?

The tangent of y^2-xy-10=0,(-3,-5) is y= 5/7 x-20/7

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tangent of y^2-xy-10=0,(-3,-5)

tangent of

y^{2} - x y - 10 = 0, (- 3, - 5)

y = \frac{5}{7} x - \frac{20}{7}

Solution steps

Find the slope of

y^{2} - x y - 10 = 0 : \frac{d y}{d x} = \frac{y}{2 y - x}

Compute the slope of

y^{2} - x y - 10 = 0

(- 3, - 5) : m = \frac{5}{7}

Find the line with slope m=

\frac{5}{7}

and passing through

(- 3, - 5) : y = \frac{5}{7} x - \frac{20}{7}

y = \frac{5}{7} x - \frac{20}{7}

y^{^{''}} + 6 y = - 294 x^{2} e^{6 x}

\int_{1}^{e^{5}} \frac{ln ( x )}{x ^{2}} d x

\frac{d}{d x} (- 4 x^{3})

x \frac{d y}{d x} + y = 9 x y^{2}, y (1) = 2

x \to 4 - lim (\frac{2 x}{x - 4})

What is the tangent of y^2-xy-10=0,(-3,-5) ?
The tangent of y^2-xy-10=0,(-3,-5) is y= 5/7 x-20/7