What is the solution for x(dy)/(dx)+y=9xy^2,y(1)=2 ?

The solution for x(dy)/(dx)+y=9xy^2,y(1)=2 is y= 2/(x(-18ln(x)+1))

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x(dy)/(dx)+y=9xy^2,y(1)=2

x \frac{d y}{d x} + y = 9 x y^{2}, y (1) = 2

y = \frac{2}{x ( - 18 ln ( x ) + 1 )}

Solution steps

x \frac{d y}{d x} + y = 9 x y^{2}

Solve Bernoulli ODE:

y = \frac{2}{x ( - 18 ln ( x ) + 1 )}

y = \frac{2}{x ( - 18 ln ( x ) + 1 )}

x \to 4 - lim (\frac{2 x}{x - 4})

f (x) = \frac{7 x}{x - 1}, (2, 14)

\frac{\partial}{\partial x} (sin (8 x) cos (4 y))

\int_{0}^{1} x (\frac{2 ( x + 1 )}{3}) d x

x \to - 2 - lim (3 x + 6 - 6)

What is the solution for x(dy)/(dx)+y=9xy^2,y(1)=2 ?
The solution for x(dy)/(dx)+y=9xy^2,y(1)=2 is y= 2/(x(-18ln(x)+1))