What is the integral of (x)arctan(x) ?

The integral of (x)arctan(x) is 1/2 x^2arctan(x)-1/2 (-arctan(x)+x)+C

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integral of (x)arctan(x)

\int (x) arctan (x) d x

\frac{1}{2} x^{2} arctan (x) - \frac{1}{2} (- arctan (x) + x) + C

Solution steps

\int x arctan (x) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} arctan (x) - \int \frac{x ^{2}}{2 ( x ^{2} + 1 )} d x

= \frac{1}{2} x^{2} arctan (x) - \int \frac{x ^{2}}{2 ( x ^{2} + 1 )} d x

\int \frac{x ^{2}}{2 ( x ^{2} + 1 )} d x = \frac{1}{2} (- arctan (x) + x)

= \frac{1}{2} x^{2} arctan (x) - \frac{1}{2} (- arctan (x) + x)

Add a constant to the solution

= \frac{1}{2} x^{2} arctan (x) - \frac{1}{2} (- arctan (x) + x) + C

\frac{d}{d x} (\frac{1}{8 x - 1})

\int e^{5 x + 2} d x

\frac{\partial}{\partial x} (cos^{6} (x^{9} y^{3}))

\int 9 + 16 x^{2} d x

\frac{\partial}{\partial x} (\frac{3 x - 2 y}{4 x ^{2} + y})

What is the integral of (x)arctan(x) ?
The integral of (x)arctan(x) is 1/2 x^2arctan(x)-1/2 (-arctan(x)+x)+C