What is the derivative of 50e^{4x}+300e^{-3x} ?

The derivative of 50e^{4x}+300e^{-3x} is 200e^{4x}-900e^{-3x}

What is the first derivative of 50e^{4x}+300e^{-3x} ?

The first derivative of 50e^{4x}+300e^{-3x} is 200e^{4x}-900e^{-3x}

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\frac{d}{d x} (50 e^{4 x} + 300 e^{- 3 x})

200 e^{4 x} - 900 e^{- 3 x}

Solution steps

\frac{d}{d x} (50 e^{4 x} + 300 e^{- 3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (50 e^{4 x}) + \frac{d}{d x} (300 e^{- 3 x})

\frac{d}{d x} (50 e^{4 x}) = 200 e^{4 x}

\frac{d}{d x} (300 e^{- 3 x}) = - 900 e^{- 3 x}

= 200 e^{4 x} - 900 e^{- 3 x}

\frac{\partial}{\partial x} (x^{2} e^{y})

e^{4 t s i n (2 t)}

\int \frac{x ^{2} + 3}{x ^{2} - 3 x + 2} d x

\int (3 x^{2} + cos (x)) d x

\frac{d}{d x} (e^{3 x s i n (2 x)})

What is the derivative of 50e^{4x}+300e^{-3x} ?
The derivative of 50e^{4x}+300e^{-3x} is 200e^{4x}-900e^{-3x}
What is the first derivative of 50e^{4x}+300e^{-3x} ?
The first derivative of 50e^{4x}+300e^{-3x} is 200e^{4x}-900e^{-3x}