What is the derivative of 16e^{2x} ?

The derivative of 16e^{2x} is 32e^{2x}

What is the first derivative of 16e^{2x} ?

The first derivative of 16e^{2x} is 32e^{2x}

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\frac{d}{d x} (16 e^{2 x})

32 e^{2 x}

Solution steps

\frac{d}{d x} (16 e^{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (e^{2 x})

Apply the chain rule:

e^{2 x} \frac{d}{d x} (2 x)

= e^{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 16 e^{2 x} \cdot 2

Simplify

= 32 e^{2 x}

y = 3 arccos (\frac{x}{2})

\frac{d y}{d x} = \frac{4 sec ( y )}{( x + 5 ) ^{2}}

(- 2.8) (- 22.8)

\frac{d}{d x} (56 x^{6})

\frac{d}{d x} (\frac{x ^{2} - 3}{x ^{2} - 4})

What is the derivative of 16e^{2x} ?
The derivative of 16e^{2x} is 32e^{2x}
What is the first derivative of 16e^{2x} ?
The first derivative of 16e^{2x} is 32e^{2x}