What is (\partial}{\partial s}(\frac{s-3r)/t) ?

The answer to (\partial}{\partial s}(\frac{s-3r)/t) is 1/t

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(\partial}{\partial s}(\frac{s-3r)/t)

\frac{\partial}{\partial s} (\frac{s - 3 r}{t})

\frac{1}{t}

Solution steps

\frac{\partial}{\partial s} (\frac{s - 3 r}{t})

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t} \frac{\partial}{\partial s} (s - 3 r)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t} (\frac{\partial}{\partial s} (s) - \frac{\partial}{\partial s} (3 r))

\frac{\partial}{\partial s} (s) = 1

\frac{\partial}{\partial s} (3 r) = 0

= \frac{1}{t} (1 - 0)

Simplify

= \frac{1}{t}

\frac{\partial}{\partial x} (y (1 - x^{2}))

x \to 2 + lim (9 - x^{2})

\int_{1}^{2} ln (3) x^{2} d x

\frac{d y}{d x} = \frac{x - 4}{y + 3}

\int \frac{x}{( x ^{2} + x + 1 )} d x

What is (\partial}{\partial s}(\frac{s-3r)/t) ?
The answer to (\partial}{\partial s}(\frac{s-3r)/t) is 1/t