What is (\partial)/(\partial x)(2y+x+1) ?

The answer to (\partial)/(\partial x)(2y+x+1) is 1

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(\partial)/(\partial x)(2y+x+1)

\frac{\partial}{\partial x} (2 y + x + 1)

1

Solution steps

\frac{\partial}{\partial x} (2 y + x + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (1) = 0

= 0 + 1 + 0

Simplify

= 1

f (X) = X

\int \frac{x e ^{2 x}}{( 2 x + 1 ) ^{2}} d x

x \frac{d y}{d x} + 2 y = x^{- 4}

f (t) = 2 t + 1

\frac{s}{( s ^{2} + 2 ^{2} ) ^{2}}

What is (\partial)/(\partial x)(2y+x+1) ?
The answer to (\partial)/(\partial x)(2y+x+1) is 1