What is the solution for x(dy)/(dx)+2y=x^{-4} ?

The solution for x(dy)/(dx)+2y=x^{-4} is y=-1/(2x^4)+(c_{1})/(x^2)

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x(dy)/(dx)+2y=x^{-4}

x \frac{d y}{d x} + 2 y = x^{- 4}

y = - \frac{1}{2 x ^{4}} + \frac{c _{1}}{x ^{2}}

Solution steps

x \frac{d y}{d x} + 2 y = x^{- 4}

Solve linear ODE:

y = - \frac{1}{2 x ^{4}} + \frac{c _{1}}{x ^{2}}

y = - \frac{1}{2 x ^{4}} + \frac{c _{1}}{x ^{2}}

f (t) = 2 t + 1

\frac{s}{( s ^{2} + 2 ^{2} ) ^{2}}

\frac{\partial}{\partial x} (e^{x c o s (y)} sin (x y))

(x^{2} - 4)^{2}

\int \frac{9 x ^{3} - x ^{2} + 45 x + 5}{x ^{3} + 5 x} d x

What is the solution for x(dy)/(dx)+2y=x^{-4} ?
The solution for x(dy)/(dx)+2y=x^{-4} is y=-1/(2x^4)+(c_{1})/(x^2)