What is the integral of tan^7(x)sec^4(x) ?

The integral of tan^7(x)sec^4(x) is (tan^8(x))/8+(tan^{10}(x))/(10)+C

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integral of tan^7(x)sec^4(x)

\int tan^{7} (x) sec^{4} (x) d x

\frac{tan ^{8} ( x )}{8} + \frac{tan ^{10} ( x )}{10} + C

Solution steps

\int tan^{7} (x) sec^{4} (x) d x

Rewrite using trig identities

= \int (1 + tan^{2} (x)) sec^{2} (x) tan^{7} (x) d x

Apply u-substitution

: \int u^{7} (1 + u^{2}) d u

= \int u^{7} (1 + u^{2}) d u

Expand

u^{7} (1 + u^{2}) : u^{7} + u^{9}

= \int u^{7} + u^{9} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{7} d u + \int u^{9} d u

\int u^{7} d u = \frac{u ^{8}}{8}

\int u^{9} d u = \frac{u ^{10}}{10}

= \frac{u ^{8}}{8} + \frac{u ^{10}}{10}

Substitute back

u = tan (x)

= \frac{tan ^{8} ( x )}{8} + \frac{tan ^{10} ( x )}{10}

Add a constant to the solution

= \frac{tan ^{8} ( x )}{8} + \frac{tan ^{10} ( x )}{10} + C

x \to - 2 lim (5 (3 x^{2} - 24 x + 3))

x \to 0 lim (\frac{- 9}{1 - 9 x})

\frac{\partial}{\partial x} (y \cdot cos (x))

\int (11 x^{10} - \frac{10}{x ^{10}}) d x

\frac{d}{d x} (3 x^{2} + 5 x - 1)

What is the integral of tan^7(x)sec^4(x) ?
The integral of tan^7(x)sec^4(x) is (tan^8(x))/8+(tan^{10}(x))/(10)+C