What is the integral from 1 to 2 of (8x^3+3x^2) ?

The integral from 1 to 2 of (8x^3+3x^2) is 37

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integral from 1 to 2 of (8x^3+3x^2)

\int_{1}^{2} (8 x^{3} + 3 x^{2}) d x

37

Solution steps

\int_{1}^{2} 8 x^{3} + 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 8 x^{3} d x + \int_{1}^{2} 3 x^{2} d x

\int_{1}^{2} 8 x^{3} d x = 30

\int_{1}^{2} 3 x^{2} d x = 7

= 30 + 7

Simplify

= 37

\frac{d}{d x} (\frac{x ^{3}}{3} - x)

n = 2 \sum \infty - (\frac{2}{3})^{n}

x \to 0 + lim (\frac{ln ( 1 + 2 x )}{x})

\frac{d}{d x} (\frac{x + y}{2 + cos ( x )})

2 t^{2} - e^{- t}

What is the integral from 1 to 2 of (8x^3+3x^2) ?
The integral from 1 to 2 of (8x^3+3x^2) is 37