What is (\partial)/(\partial y)(cos(x+y)) ?

The answer to (\partial)/(\partial y)(cos(x+y)) is -sin(x+y)

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(\partial)/(\partial y)(cos(x+y))

\frac{\partial}{\partial y} (cos (x + y))

- sin (x + y)

Solution steps

\frac{\partial}{\partial y} (cos (x + y))

Treat

x

as a constant

Apply the chain rule:

- sin (x + y) \frac{\partial}{\partial y} (x + y)

= - sin (x + y) \frac{\partial}{\partial y} (x + y)

\frac{\partial}{\partial y} (x + y) = 1

= - sin (x + y) \cdot 1

Simplify

= - sin (x + y)

\frac{d}{d x} (36 - x^{2})

\frac{\partial}{\partial x} (y^{4} cos (4 x))

\frac{\partial}{\partial x} (e^{(x y)})

\int sin (t) e^{t} d t

\frac{12}{3 s - 5}

What is (\partial)/(\partial y)(cos(x+y)) ?
The answer to (\partial)/(\partial y)(cos(x+y)) is -sin(x+y)