What is the derivative of y=6sqrt(4+x) ?

The derivative of y=6sqrt(4+x) is 3/(sqrt(4+x))

What is the first derivative of y=6sqrt(4+x) ?

The first derivative of y=6sqrt(4+x) is 3/(sqrt(4+x))

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derivative of

y = 6 4 + x

\frac{3}{4 + x}

Solution steps

\frac{d}{d x} (6 4 + x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (4 + x)

Apply the chain rule:

\frac{1}{2 4 + x} \frac{d}{d x} (4 + x)

= \frac{1}{2 4 + x} \frac{d}{d x} (4 + x)

\frac{d}{d x} (4 + x) = 1

= 6 \cdot \frac{1}{2 4 + x} \cdot 1

Simplify

6 \cdot \frac{1}{2 4 + x} \cdot 1 : \frac{3}{4 + x}

= \frac{3}{4 + x}

\frac{d}{d x} (\frac{cos ( x )}{x ^{2} + 1})

o 2 x 2 - 3 x + 2

\frac{\partial}{\partial y} (2 yz)

\int \frac{x ^{2} + 2 x - 3}{x + 1} d x

What is the derivative of y=6sqrt(4+x) ?
The derivative of y=6sqrt(4+x) is 3/(sqrt(4+x))
What is the first derivative of y=6sqrt(4+x) ?
The first derivative of y=6sqrt(4+x) is 3/(sqrt(4+x))