What is the derivative of tan(x+1) ?

The derivative of tan(x+1) is sec^2(x)

What is the first derivative of tan(x+1) ?

The first derivative of tan(x+1) is sec^2(x)

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\frac{d}{d x} (tan (x) + 1)

sec^{2} (x)

Solution steps

\frac{d}{d x} (tan (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (1) = 0

= sec^{2} (x) + 0

Simplify

= sec^{2} (x)

y = \frac{2}{e ^{x}}

x \to 7 lim (7^{x} + 12 (x))

\frac{\partial}{\partial y} (100 e^{- x - 2 y})

\int \frac{( - 1 ) ^{n} x ^{2 n}}{n !} d x

\int x e^{x^{2}} d x

What is the derivative of tan(x+1) ?
The derivative of tan(x+1) is sec^2(x)
What is the first derivative of tan(x+1) ?
The first derivative of tan(x+1) is sec^2(x)