What is (\partial)/(\partial y)(2xy^4-3) ?

The answer to (\partial)/(\partial y)(2xy^4-3) is 8xy^3

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(\partial)/(\partial y)(2xy^4-3)

\frac{\partial}{\partial y} (2 x y^{4} - 3)

8 x y^{3}

Solution steps

\frac{\partial}{\partial y} (2 x y^{4} - 3)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y^{4}) - \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (2 x y^{4}) = 8 x y^{3}

\frac{\partial}{\partial y} (3) = 0

= 8 x y^{3} - 0

Simplify

= 8 x y^{3}

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What is (\partial)/(\partial y)(2xy^4-3) ?
The answer to (\partial)/(\partial y)(2xy^4-3) is 8xy^3