What is the solution for y^'+6(tan(6x))y=4cos(6x) ?

The solution for y^'+6(tan(6x))y=4cos(6x) is y=(4x)/(sec(6x))+(c_{1})/(sec(6x))

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y^'+6(tan(6x))y=4cos(6x)

y^{^{'}} + 6 (tan (6 x)) y = 4 cos (6 x)

y = \frac{4 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

Solution steps

y^{'} (x) + 6 (tan (6 x)) y = 4 cos (6 x)

Solve linear ODE:

y = \frac{4 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

y = \frac{4 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

\int sin (x) e^{- 2 x} d x

\int \frac{5 x ^{3} + 7 x + 2}{x ^{4} + 9 x ^{2}} d x

\frac{2}{( s + 1 ) ( s + 2 )}

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What is the solution for y^'+6(tan(6x))y=4cos(6x) ?
The solution for y^'+6(tan(6x))y=4cos(6x) is y=(4x)/(sec(6x))+(c_{1})/(sec(6x))