What is (\partial)/(\partial u)(sin^2(u)) ?

The answer to (\partial)/(\partial u)(sin^2(u)) is sin(2u)

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(\partial)/(\partial u)(sin^2(u))

\frac{\partial}{\partial u} (sin^{2} (u))

sin (2 u)

Solution steps

\frac{\partial}{\partial u} (sin^{2} (u))

Apply the chain rule:

2 sin (u) \frac{\partial}{\partial u} (sin (u))

= 2 sin (u) \frac{\partial}{\partial u} (sin (u))

\frac{\partial}{\partial u} (sin (u)) = cos (u)

= 2 sin (u) cos (u)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 u)

18 cos (x) + 9 sin (2 x)

\frac{d y}{d x} = \frac{x - a}{y - b}

\int_{0}^{4 π} \frac{1}{2}

n = 1 \sum \infty \frac{n ^{2}}{6 ^{n}}

y = 7 x e^{x}, (0, 0)

What is (\partial)/(\partial u)(sin^2(u)) ?
The answer to (\partial)/(\partial u)(sin^2(u)) is sin(2u)