What is the derivative of ln(4^x) ?

The derivative of ln(4^x) is 2ln(2)

What is the first derivative of ln(4^x) ?

The first derivative of ln(4^x) is 2ln(2)

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\frac{d}{d x} (ln (4^{x}))

2 ln (2)

Solution steps

\frac{d}{d x} (ln (4^{x}))

Simplify

ln (4^{x}) : 2 ln (2) x

= \frac{d}{d x} (2 ln (2) x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 ln (2) \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 ln (2) \cdot 1

Simplify

= 2 ln (2)

\int \frac{6}{x ^{2} x ^{2} + 9} d x

d x = e^{3 x} d y

\int s 8^{s} d s

\int \frac{x ^{2}}{x ^{2} + 2} d x

y = 3 - 6 x

What is the derivative of ln(4^x) ?
The derivative of ln(4^x) is 2ln(2)
What is the first derivative of ln(4^x) ?
The first derivative of ln(4^x) is 2ln(2)