What is the integral of-3tan^2(x) ?

The integral of-3tan^2(x) is -3(-x+tan(x))+C

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integral of-3tan^2(x)

\int - 3 tan^{2} (x) d x

- 3 (- x + tan (x)) + C

Solution steps

\int - 3 tan^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int tan^{2} (x) d x

Rewrite using trig identities

= - 3 \cdot \int - 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - 3 (- \int 1 d x + \int sec^{2} (x) d x)

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= - 3 (- x + tan (x))

Add a constant to the solution

= - 3 (- x + tan (x)) + C

\frac{d}{d x} (tan (7 x))

\frac{d}{d x} (2 x^{2} - 8 x + 5)

\frac{d}{d x} (\frac{3 x}{π})

b \to 1 lim (ln (ln (b)))

f (x) = \frac{5}{3 x}, at x = 1

What is the integral of-3tan^2(x) ?
The integral of-3tan^2(x) is -3(-x+tan(x))+C