What is the derivative of sin(bx) ?

The derivative of sin(bx) is cos(bx)b

What is the first derivative of sin(bx) ?

The first derivative of sin(bx) is cos(bx)b

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derivative of

sin (b x)

cos (b x) b

Solution steps

\frac{d}{d x} (sin (b x))

Apply the chain rule:

cos (b x) \frac{d}{d x} (b x)

= cos (b x) \frac{d}{d x} (b x)

\frac{d}{d x} (b x) = b

= cos (b x) b

2 x - 1

\int \frac{1}{x ^{2} - 6 x + 13} d x

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = - 4, y^{^{'}} (0) = 2

\frac{\partial}{\partial x} (x^{2} \cdot y)

\int x e^{(2 x)} d x

What is the derivative of sin(bx) ?
The derivative of sin(bx) is cos(bx)b
What is the first derivative of sin(bx) ?
The first derivative of sin(bx) is cos(bx)b