What is the derivative of f(x)=2x^3+1 ?

The derivative of f(x)=2x^3+1 is 6x^2

What is the first derivative of f(x)=2x^3+1 ?

The first derivative of f(x)=2x^3+1 is 6x^2

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derivative of

f (x) = 2 x^{3} + 1

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (1) = 0

= 6 x^{2} + 0

Simplify

= 6 x^{2}

\int - \frac{4}{x ^{5}} d x

f (x) = - 3 x^{4}

\int_{0}^{π} 9 sin^{4} (x) d x

y = (cos (7 x))^{x}

\frac{x + 6}{5}, ∣ x ∣

What is the derivative of f(x)=2x^3+1 ?
The derivative of f(x)=2x^3+1 is 6x^2
What is the first derivative of f(x)=2x^3+1 ?
The first derivative of f(x)=2x^3+1 is 6x^2