What is area f(x)=9-x^2,g(x)=-8x ?

The answer to area f(x)=9-x^2,g(x)=-8x is 500/3

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area f(x)=9-x^2,g(x)=-8x

area

f (x) = 9 - x^{2}, g (x) = - 8 x

\frac{500}{3}

Decimal Notation

166.66666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{9} 9 - x^{2} + 8 x d x

Solve

\int_{- 1}^{9} 9 - x^{2} + 8 x d x : \frac{500}{3}

The area is:

= \frac{500}{3}

\int x^{5} d x

T

\frac{x}{cos ( x )}

f (x) = x^{- 1} - x

\int t - sin (t) d t

What is area f(x)=9-x^2,g(x)=-8x ?
The answer to area f(x)=9-x^2,g(x)=-8x is 500/3