What is the derivative of (3x+7^2) ?

The derivative of (3x+7^2) is 6(3x+7)

What is the first derivative of (3x+7^2) ?

The first derivative of (3x+7^2) is 6(3x+7)

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\frac{d}{d x} ((3 x + 7)^{2})

6 (3 x + 7)

Solution steps

\frac{d}{d x} ((3 x + 7)^{2})

Apply the chain rule:

2 (3 x + 7) \frac{d}{d x} (3 x + 7)

= 2 (3 x + 7) \frac{d}{d x} (3 x + 7)

\frac{d}{d x} (3 x + 7) = 3

= 2 (3 x + 7) \cdot 3

Simplify

= 6 (3 x + 7)

\int_{- 9}^{0} y + 9 d y

x \to 3 lim (x^{2} + 8 x - 2)

n = 5 \sum \infty \frac{2}{n ^{2} - 1}

\int \frac{x}{5 x - 2} d x

\int_{\frac{1}{3}}^{7} 6 x ln (3 x) d x

What is the derivative of (3x+7^2) ?
The derivative of (3x+7^2) is 6(3x+7)
What is the first derivative of (3x+7^2) ?
The first derivative of (3x+7^2) is 6(3x+7)