What is the derivative of (x^4)/4+7/6 x^3-x^2+6x-8 ?

The derivative of (x^4)/4+7/6 x^3-x^2+6x-8 is x^3+(7x^2)/2-2x+6

What is the first derivative of (x^4)/4+7/6 x^3-x^2+6x-8 ?

The first derivative of (x^4)/4+7/6 x^3-x^2+6x-8 is x^3+(7x^2)/2-2x+6

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derivative of

\frac{x ^{4}}{4} + \frac{7}{6} x^{3} - x^{2} + 6 x - 8

x^{3} + \frac{7 x ^{2}}{2} - 2 x + 6

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{4} + \frac{7}{6} x^{3} - x^{2} + 6 x - 8)

Simplify

\frac{x ^{4}}{4} + \frac{7}{6} x^{3} - x^{2} + 6 x - 8 : \frac{x ^{4}}{4} + \frac{7 x ^{3}}{6} - x^{2} + 6 x - 8

= \frac{d}{d x} (\frac{x ^{4}}{4} + \frac{7 x ^{3}}{6} - x^{2} + 6 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{4}) + \frac{d}{d x} (\frac{7 x ^{3}}{6}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (8)

\frac{d}{d x} (\frac{x ^{4}}{4}) = x^{3}

\frac{d}{d x} (\frac{7 x ^{3}}{6}) = \frac{7 x ^{2}}{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (8) = 0

= x^{3} + \frac{7 x ^{2}}{2} - 2 x + 6 - 0

Simplify

= x^{3} + \frac{7 x ^{2}}{2} - 2 x + 6

x \cdot 3^{x^{2} + 1}

6 (t + 1) (\frac{d y}{d t}) - 5 y = 5 t

x \to \frac{π}{2} lim (cos (3 x))

(1 + p^{2}) (x + e^{- x}) - 10

\int e^{x} sin^{2} (e^{x}) d x

What is the derivative of (x^4)/4+7/6 x^3-x^2+6x-8 ?
The derivative of (x^4)/4+7/6 x^3-x^2+6x-8 is x^3+(7x^2)/2-2x+6
What is the first derivative of (x^4)/4+7/6 x^3-x^2+6x-8 ?
The first derivative of (x^4)/4+7/6 x^3-x^2+6x-8 is x^3+(7x^2)/2-2x+6