What is the derivative of ln(-5x) ?

The derivative of ln(-5x) is 1/x

What is the first derivative of ln(-5x) ?

The first derivative of ln(-5x) is 1/x

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\frac{d}{d x} (ln (- 5 x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (- 5 x))

Apply the chain rule:

\frac{1}{- 5 x} \frac{d}{d x} (- 5 x)

= \frac{1}{- 5 x} \frac{d}{d x} (- 5 x)

\frac{d}{d x} (- 5 x) = - 5

= \frac{1}{- 5 x} (- 5)

Simplify

\frac{1}{- 5 x} (- 5) : \frac{1}{x}

= \frac{1}{x}

\frac{\frac{1}{3}}{s}

t \cdot \frac{d y}{d t} = t^{3} + 30 t^{3} y

n = 0 \sum \infty n! (x - 3)^{n}

f (x) = 2 x^{\frac{1}{3}} + \frac{x}{3} - \frac{1}{4} x^{3}

\int - 7 (- 7 x)^{3} d x

What is the derivative of ln(-5x) ?
The derivative of ln(-5x) is 1/x
What is the first derivative of ln(-5x) ?
The first derivative of ln(-5x) is 1/x