What is the integral of-7(-7x)^3 ?

The integral of-7(-7x)^3 is (2401x^4)/4+C

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integral of-7(-7x)^3

\int - 7 (- 7 x)^{3} d x

\frac{2401 x ^{4}}{4} + C

Solution steps

\int - 7 (- 7 x)^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 7 \cdot \int (- 7 x)^{3} d x

Simplify

(- 7 x)^{3} : - 343 x^{3}

= - 7 \cdot \int - 343 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 7 (- 343 \cdot \int x^{3} d x)

Apply the Power Rule

: \frac{x ^{4}}{4}

= - 7 (- 343 \cdot \frac{x ^{4}}{4})

Simplify

- 7 (- 343 \cdot \frac{x ^{4}}{4}) : \frac{2401 x ^{4}}{4}

= \frac{2401 x ^{4}}{4}

Add a constant to the solution

= \frac{2401 x ^{4}}{4} + C

\frac{d}{d x} (x^{4} e^{9 x})

\frac{d}{d x} (\frac{6}{7 x ^{4}})

\int (2 x^{2} - 3 x + 2)^{\frac{3}{2}} (x - \frac{3}{4}) d x

\frac{\partial}{\partial y} (\frac{2 x - 2 z}{3 y + 2 z})

y = 2 x^{2} - 4 x + 2