What is the derivative of y=2x^2-4x+2 ?

The derivative of y=2x^2-4x+2 is 4x-4

What is the first derivative of y=2x^2-4x+2 ?

The first derivative of y=2x^2-4x+2 is 4x-4

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derivative of

y = 2 x^{2} - 4 x + 2

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

\int \frac{( ln ( x ) ) ^{25}}{x} d x

\int_{1}^{2} w^{5} e^{w^{3}} d w

\frac{d y}{d x} - e^{2 x} = 3, y (0) = 4

x \to - 2 lim (\frac{x ^{2}}{x ^{2} + 2})

y = \frac{1}{x ^{6}}, (- 3, \frac{1}{729})

What is the derivative of y=2x^2-4x+2 ?
The derivative of y=2x^2-4x+2 is 4x-4
What is the first derivative of y=2x^2-4x+2 ?
The first derivative of y=2x^2-4x+2 is 4x-4