What is the derivative of-x^2+8x-12 ?

The derivative of-x^2+8x-12 is -2x+8

What is the first derivative of-x^2+8x-12 ?

The first derivative of-x^2+8x-12 is -2x+8

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\frac{d}{d x} (- x^{2} + 8 x - 12)

- 2 x + 8

Solution steps

\frac{d}{d x} (- x^{2} + 8 x - 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (12)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (12) = 0

= - 2 x + 8 - 0

Simplify

= - 2 x + 8

\frac{d}{d x} (2 x - 5)

y = x^{3} - 3 x + 5, (3, 23)

f (x) = \frac{x}{x ^{2} + 1}, at x = 0

\int \frac{1}{1 - v} d v

\frac{1}{s ( s + \frac{1}{15} )}

What is the derivative of-x^2+8x-12 ?
The derivative of-x^2+8x-12 is -2x+8
What is the first derivative of-x^2+8x-12 ?
The first derivative of-x^2+8x-12 is -2x+8