What is the derivative of sqrt(8x^2+1) ?

The derivative of sqrt(8x^2+1) is (8x)/(sqrt(8x^2+1))

What is the first derivative of sqrt(8x^2+1) ?

The first derivative of sqrt(8x^2+1) is (8x)/(sqrt(8x^2+1))

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\frac{d}{d x} (8 x^{2} + 1)

\frac{8 x}{8 x ^{2} + 1}

Solution steps

\frac{d}{d x} (8 x^{2} + 1)

Apply the chain rule:

\frac{1}{2 8 x ^{2} + 1} \frac{d}{d x} (8 x^{2} + 1)

= \frac{1}{2 8 x ^{2} + 1} \frac{d}{d x} (8 x^{2} + 1)

\frac{d}{d x} (8 x^{2} + 1) = 16 x

= \frac{1}{2 8 x ^{2} + 1} \cdot 16 x

Simplify

\frac{1}{2 8 x ^{2} + 1} \cdot 16 x : \frac{8 x}{8 x ^{2} + 1}

= \frac{8 x}{8 x ^{2} + 1}

\frac{d}{d x} ((sin (2 x)) (cos (2 x)))

\frac{\partial}{\partial x} (x^{0.9})

\frac{1}{1 - L S}

\frac{d}{d x} (\frac{- 9}{x ^{2}})

\int e^{- 2 t} d t

What is the derivative of sqrt(8x^2+1) ?
The derivative of sqrt(8x^2+1) is (8x)/(sqrt(8x^2+1))
What is the first derivative of sqrt(8x^2+1) ?
The first derivative of sqrt(8x^2+1) is (8x)/(sqrt(8x^2+1))